Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.3 Measures of Dispersion - Exercise Set 12.3 - Page 800: 13

Answer

See below.

Work Step by Step

a) The mean of $n$ numbers is the sum of the numbers divided by $n$. Hence the mean: $\frac{146+153+155+160+161}{5}=155$ b) The deviation is the difference of the data item and the mean. Hence here the deviations: $146-155=-9,153-155=-2,155-155=0,160-155=5,161-155=6$ c) The sums of the deviations: $-9-2+0+5+6=11$
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