Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.3 Measures of Dispersion - Exercise Set 12.3 - Page 800: 12

Answer

See below.

Work Step by Step

a) The mean of $n$ numbers is the sum of the numbers divided by $n$. Hence the mean: $\frac{94+62+88+85+91 }{5}=84$ b) The deviation is the difference of the data item and the mean. Hence here the deviations: $94-84=10,62-84=-22,88-84=4,85-84=1,91-84=7$ c) The sums of the deviations: 10-22+4+1+7=0$
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