Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.3 Measures of Dispersion - Exercise Set 12.3 - Page 800: 15

Answer

See below.

Work Step by Step

a) The mean of $n$ numbers is the sum of the numbers divided by $n$. Hence the mean: $\frac{2.25+3.50+2.75+3.10+1.90 }{5}=2.7$ b) The deviation is the difference of the data item and the mean. Hence here the deviations: $2.25-2.7=-0.45,3.5-2.7=0.8,2.75-2.7=0.05,3.1-2.7=0.4,1.9-2.7=-0.8$ c) The sums of the deviations: $-0.45+0.8+0.05+0.4-0.8=0$
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