Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.3 Measures of Dispersion - Exercise Set 12.3 - Page 800: 16

Answer

See below.

Work Step by Step

a) The mean of $n$ numbers is the sum of the numbers divided by $n$. Hence the mean: $\frac{0.35+0.37+0.41+0.39+0.43}{5}=0.39$ b) The deviation is the difference of the data item and the mean. Hence here the deviations: $0.35-0.39=-0.04, 0.37-0.39=-0.02, 0.41-0.39=0.02, 0.39-0.39=0, 0.43-0.39=0.04 $ c) The sums of the deviations: $-0.04-0.02+0.02+0+0.04=0$
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