## Thinking Mathematically (6th Edition)

$\frac{1}{12}$
If A, B, and C are independent events, then P(E) = P(A)*P(B)*P(C) E: Red and then red and then green. A: red B: red C: green P(A) = $\frac{3}{6}$ P(B) = $\frac{3}{6}$ P(C) = $\frac{2}{6}$ Both events A and B are independent: P(E) = $\frac{3}{6}$ .$\frac{3}{6}$ . $\frac{2}{6}$ = $\frac{1}{12}$