Thinking Mathematically (6th Edition)

$\frac{1}{36}$
If A and B are independent events, then P(E) = P(A)*P(B) A: 5 first time B: 1 second time P(A) = $\frac{1}{6}$ P(B) = $\frac{1}{6}$ Both events A and B are independent, so P(E) = $\frac{1}{6}$ .$\frac{1}{6}$ = $\frac{1}{36}$