## Thinking Mathematically (6th Edition)

$\frac{1}{3}$
If A and B are independent events, then P(E) = P(A)*P(B). A: {2,4,6} first time P(A) = $\frac{3}{6}$ B: A number greater than 2 the second role. P(B) = $\frac{4}{6}$ Both events A and B are independent, so P(E) = $\frac{3}{6}$ .$\frac{4}{6}$ = $\frac{1}{3}$