Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7: 14

Answer

$\frac{1}{6}$

Work Step by Step

If A and B are independent events, then P(E) = P(A)*P(B). A: {1,3,5} (An odd number the first time.) B: {1,2} (A number less than 3.) P(A) = $\frac{3}{6}$ P(B) = $\frac{2}{6}$ Both events A and B are independent, so P(E) = $\frac{3}{6}$ .$\frac{2}{6}$ = $\frac{1}{6}$
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