#### Answer

$\frac{1}{64}$

#### Work Step by Step

P(E) = P(A)*P(B)
Assume that we are flipping a coin in a fair manner. Find the probability of some series of events, E, happening. Let A be the first event, B be the second event, and so on.
We consider the chances of getting heads six times in a row:
P(A) =P(B)=P(C)=P(D)=P(E)=P(F)= $\frac{1}{2}$
P(E) = P(A)*P(B)*P(C)*P(D)*P(E)*P(F)
P(E) = $\frac{1}{2^{6}}$
= $\frac{1}{64}$