## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7: 7

#### Answer

$\frac{1}{36}$

#### Work Step by Step

If A, B and C are independent events, then P(E) = P(A)*P(B)*P(C) E: green and then red and then yellow. A: green B: red C: yellow P(A) = $\frac{2}{6}$ P(B) = $\frac{3}{6}$ P(C) = $\frac{1}{6}$ Events A, B, and C are independent: P(E) = $\frac{2}{6}$ .$\frac{3}{6}$ . $\frac{1}{6}$ = $\frac{1}{36}$

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