Answer
$\dfrac{1}{10}$ or, $10 \%$
Work Step by Step
The probability that $P$ lies on the segment $\overline{FG}$ can be computed as:
$P(\text{point on $\overline{FG}$})=\dfrac{FG}{AK}$
Where, $FG=6-5=1$ and $Ak=10-0=10$
Now, $P(\text{point on $\overline{FG}$})=\dfrac{1}{10}$ or, $10 \%$
