Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-8 Geometric Probability - Practice and Problem-Solving Exercises - Page 671: 8

Answer

$\dfrac{1}{2}$ or, $50 \%$

Work Step by Step

The probability that the point $T$ lies in the segment $\overline{CH}$ can be computed as: $P(\text{point on $\overline{CH}$})=\dfrac{CH}{AK}$ Where, $CH=7-2=5$ and $Ak=10-0=10$ Now, $P(\text{point on $\overline{CH}$})=\dfrac{CH}{AK}=\dfrac{5}{10}=\dfrac{1}{2}$ or, $50 \%$
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