Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-8 Geometric Probability - Practice and Problem-Solving Exercises - Page 671: 12

Answer

$1$ or, $100 \%$

Work Step by Step

The probability that $P$ lies on the segment $\overline{AK}$ can be computed as: $P(\text{point on $\overline{AK}$})=\dfrac{AK}{AK}$ Where, $AK=10-0=0$ and $Ak=10-0=10$ Now, $P(\text{point on $\overline{AK}$})=\dfrac{AK}{AK}=\dfrac{10}{10}=1$ or, $100 \%$
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