Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-8 Geometric Probability - Practice and Problem-Solving Exercises - Page 671: 11

Answer

$\dfrac{2}{5}$ or, $40 \%$

Work Step by Step

The probability that the $P$ lies on the segment $\overline{EI}$ can be computed as: $P(\text{point on $\overline{EI}$})=\dfrac{EI}{AK}$ Where, $EI=8-4=4$ and $Ak=10-0=10$ Now, $P(\text{point on $\overline{EI}$})=\dfrac{EI}{AK}=\dfrac{4}{10}=\dfrac{2}{5}$ $=40 \%$
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