Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Appendix A - A.4 - Quadratic Equations - Exercises - Page 560: 26

Answer

$x=3.87; x=0.13 $

Work Step by Step

$x=\frac{-b+\sqrt (b^{2}-4ac)}{2a}$ $x=\frac{-b-\sqrt (b^{2}-4ac)}{2a}$ a= 2 b= -8 c= 1 $x=\frac{8+7.48}{4}$ $x=\frac{8-7.48}{4}$
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