Answer
$x = \frac{2}{3}, -\frac{3}{2}$
Work Step by Step
$12x^{2} + 10x = 12$
$12x^{2} + 10x - 12= 0$
$2(6x^{2} + 5x - 6) = 0$
Find two numbers that can be multiplied together to get $-36$ and can be added together to get $5$.
$= -4$ and $9$
$2[6x^{2} - 4x + 9x - 6] = 0$
$2[2x(3x - 2) + 3(3x - 2)] = 0$
$2(2x + 3)(3x-2) = 0$
$2x + 3 = 0$
$2x = -3$
$x = -\frac{3}{2}$
$3x - 2 = 0$
$3x = 2$
$x = \frac{2}{3}$
$x = \frac{2}{3}, -\frac{3}{2}$
