Answer
$x = -\frac{2}{3}, 4$
Work Step by Step
$3x^{2} = 10x + 8$
$3x^{2} - 10x - 8 = 0$
Find two numbers that can be multiplied together to get $-24$ and can be added together to get $-10$.
$= 2$ and $-12$
$3x^{2} + 2x - 12x - 8 = 0$
$x(3x + 2) - 4(3x + 2) = 0$
$(3x + 2)(x-4) = 0$
$x = -\frac{2}{3}, 4$
$3x + 2 = 0$
$3x = -2$
$x = -\frac{2}{3}$
