Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Appendix A - A.4 - Quadratic Equations - Exercises - Page 560: 23

Answer

$x=5.46; x=-1.46$

Work Step by Step

$x=\frac{-b+\sqrt (b^{2}-4ac)}{2a}$ $x=\frac{-b-\sqrt (b^{2}-4ac)}{2a}$ a= 1 b= -4 c= -8 $x=\frac{4+6.93}{2}$ $x=\frac{4-6.93}{2}$
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