## Elementary Geometry for College Students (5th Edition)

$x = \frac{3}{2}, -2$
$2x^{2} + x - 6= 0$ Find two numbers that multiply to $((-6) \times 2 = -12)$ and can be added together to get $1$. $= -3$ and $4$ $2x^{2} - 3x + 4x - 6= 0$ $x(2x - 3) + 2(2x - 3) = 0$ $(2x - 3)(x+2) = 0$ $x = \frac{3}{2}, -2$ $2x - 3 = 0$ $2x = 3$ $x = \frac{3}{2}$