Answer
$x = \frac{3}{2}, -2$
Work Step by Step
$2x^{2} + x - 6= 0$
Find two numbers that multiply to $((-6) \times 2 = -12)$ and can be added together to get $1$.
$= -3$ and $4$
$2x^{2} - 3x + 4x - 6= 0$
$x(2x - 3) + 2(2x - 3) = 0$
$(2x - 3)(x+2) = 0$
$x = \frac{3}{2}, -2$
$2x - 3 = 0$
$2x = 3$
$x = \frac{3}{2}$
