# Appendix A - A.4 - Quadratic Equations - Exercises - Page 556: 7

$4x^2-49y^2 = (2x+7y)~(2x-7y)$

#### Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ We can factor the difference of the two squares: $4x^2-49y^2 = (2x+7y)~(2x-7y)$

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