#### Answer

$4x^2-49y^2 = (2x+7y)~(2x-7y)$

#### Work Step by Step

The general form of factoring the difference of two squares is as follows:
$x^2-y^2 = (x+y)~(x-y)$
We can factor the difference of the two squares:
$4x^2-49y^2 = (2x+7y)~(2x-7y)$

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Published by
Cengage

ISBN 10:
978-1-337-61408-5

ISBN 13:
978-1-33761-408-5

$4x^2-49y^2 = (2x+7y)~(2x-7y)$

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