Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Appendix A - A.4 - Quadratic Equations - Exercises - Page 556: 6

Answer

$16x^2-9y^2 = (4x+3y)~(4x-3y)$

Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ We can factor the difference of the two squares: $16x^2-9y^2 = (4x+3y)~(4x-3y)$
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