Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Appendix A - A.4 - Quadratic Equations - Exercises - Page 556: 24


$x^3-9x = (x)~(x+3)~(x-3)$

Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ Let's consider this trinomial: $~x^3-9x$ First we can factor by using the GCF: $x^3-9x = (x)~(x^2-9)$ Then we can factor by using the difference of two squares. We can factor the trinomial as follows: $x^3-9x = (x)~(x^2-9)$ $x^3-9x = (x)~(x+3)~(x-3)$
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