Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Appendix A - A.4 - Quadratic Equations - Exercises - Page 556: 9

Answer

$x^2+7x+12 = (x+3)~(x+4)$

Work Step by Step

Let's consider a trinomial in this form: $~x^2+bx+c$ To factor this trinomial, we need to find two numbers $r$ and $s$ such that $r+s = b$ and $r\times s = c$ Then we can factor the trinomial as follows: $~x^2+bx+c = (x+r)~(x+s)$ Let's consider this trinomial: $~x^2+7x+12$ To factor this trinomial, we need to find two numbers $r$ and $s$ such that $r+s = 7$ and $r\times s = 12$. We can see that $3+4 = 7$ and $3\times 4 = 12$ We can factor the trinomial as follows: $x^2+7x+12 = (x+3)~(x+4)$
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