Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Appendix A - A.4 - Quadratic Equations - Exercises - Page 556: 18

Answer

$6y^2-54 = (6)~(y+3)~(y-3)$

Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ We can factor the expression by using the GCF and then factoring the difference of two squares: $6y^2-54 = (6)(y^2-9)$ $6y^2-54 = (6)~(y+3)~(y-3)$
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