Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Review Exercises - Page 263: 40a


x=9$\sqrt 2$ y=9

Work Step by Step

In a 30 60 90 triangle the short leg is equal to the long leg divided by the square root of 3, therefore: y=9. The hypotenuse of a 30 60 90 triangle is equal to twice the short leg, therefore: hypotenuse=18. The legs of a 45 45 90 triangle are equal to the hypotenuse divided by the square root of 2 therefore: x=$\frac{18}{\sqrt 2}$. x=9$\sqrt 2$
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