## Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole

# Chapter 5 - Review Exercises - Page 263: 30c

#### Answer

BA=3$\sqrt 2$

#### Work Step by Step

$\frac{BD}{BA}$=$\frac{BA}{BC}$ $\frac{3}{BA}$=$\frac{BA}{6}$ BA$^2$=18 BA=3$\sqrt 2$

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