Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Review Exercises - Page 263: 30c


BA=3$\sqrt 2$

Work Step by Step

$\frac{BD}{BA}$=$\frac{BA}{BC}$ $\frac{3}{BA}$=$\frac{BA}{6}$ BA$^2$=18 BA=3$\sqrt 2$
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