Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Review Exercises - Page 263: 30b



Work Step by Step

AD$^2$=AC$^2$-DC$^2$ AD=8 $\frac{BD}{AD}$=$\frac{AD}{AC}$ $\frac{BD}{8}$=$\frac{8}{10}$ 10BD=64 BD=6.4
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