Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Review Exercises - Page 263: 30d



Work Step by Step

$\frac{BD+DC}{AC}$=$\frac{AC}{DC}$ 3DC+DC$^2$=18 DC$^2$+3DC-18=0 (DC+6)(DC-3)=0 DC=3
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