Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Review Exercises - Page 263: 33

Answer

AE=20 EF=15 AF=25

Work Step by Step

AE$^2$=AB$^2$+BE$^2$ AE$^2$=256+144 AE=20 EF$^2$=EC$^2$+CF$^2$ EF$^2$=144+81 EF=15 AF$^2$=FD$^2$+AD$^2$ AF$^2$=49+576 AF=25
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