Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Review Exercises - Page 263: 31d



Work Step by Step

$\frac{AD+DC}{AB}$=$\frac{AB}{AD}$ $\frac{AD+2}{2\sqrt 6}$=$\frac{2\sqrt 6}{AD}$ AD$^2$+2AD-24=0 (AD+6)(AD-4)=0 AD=4
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.