Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 8b

Answer

$\frac{sine α}{a}$ = $\frac{sine β}{b}$

Work Step by Step

We know the values of a,α, β We need to find the value of b By using theorem 11.4.2 Law of Sines $\frac{sine α}{a}$ = $\frac{sine β}{b}$
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