Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 3a

Answer

$\frac{sine 40°}{5}$ = $\frac{sine β}{8}$

Work Step by Step

Given a=5 b=8 and α =40° By law of sines $\frac{sine α}{a}$ = $\frac{sine β}{b}$ $\frac{sine 40°}{5}$ = $\frac{sine β}{8}$
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