Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 3a

Answer

$\frac{sine 40°}{5}$ = $\frac{sine β}{8}$

Work Step by Step

Given a=5 b=8 and α =40° By law of sines $\frac{sine α}{a}$ = $\frac{sine β}{b}$ $\frac{sine 40°}{5}$ = $\frac{sine β}{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.