#### Answer

$8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β

#### Work Step by Step

Given data
a=6,b =8, c=9
Using theorem 11.4.3
In triangle ABC
$b^{2}$ = $a^{2}$ + $c^{2}$ - 2ac cos β
$8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β

Published by
Brooks Cole

ISBN 10:

ISBN 13:

$8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β

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