Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 4a

Answer

$\frac{sine β}{8.1}$ = $\frac{sine 86°}{8.4}$

Work Step by Step

Given b=8.1, c=8.4, γ=86° Using theorem 11.4.2 By law of sines $\frac{sine β}{b}$ = $\frac{sine γ}{c}$ $\frac{sine β}{8.1}$ = $\frac{sine 86°}{8.4}$
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