Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 2a

Answer

Area = $\frac{1}{2}$*(7.3)*(8.6)*sin 38°

Work Step by Step

Given, b=7.3, c=8.6, α = 38° By theorem 11.4.1 Area of triangle = $\frac{1}{2}$b*c*sinα =$\frac{1}{2}$*(7.3)*(8.6)*sin 38°
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