Answer
$6^{2}$ = $9^{2}$ + $10^{2}$ + 2*9*10*cos α
Work Step by Step
given data a= 6,b=9 ,c= 10
using theorem 11.4.3
$a^{2}$ = $b^{2}$ + $c^{2}$ + 2bc cos α
$6^{2}$ = $9^{2}$ + $10^{2}$ + 2*9*10*cos α
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 5b
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