Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 5b

Answer

$6^{2}$ = $9^{2}$ + $10^{2}$ + 2*9*10*cos α

Work Step by Step

given data a= 6,b=9 ,c= 10 using theorem 11.4.3 $a^{2}$ = $b^{2}$ + $c^{2}$ + 2bc cos α $6^{2}$ = $9^{2}$ + $10^{2}$ + 2*9*10*cos α
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