University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.1 - Sequences - Exercises - Page 487: 4

Answer

$a_1=1$ $a_2=3$ $a_3=1$ $a_4=3$

Work Step by Step

We know that $a_n=2+(-1)^n$. Hence, here: $a_1=2+(-1)^1=2+(-1)=1$ $a_2=2+(-1)^2=2+1=3$ $a_3=2+(-1)^3=2+(-1)=1$ $a_4=2+(-1)^4=2+1=3$
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