University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.1 - Sequences - Exercises - Page 487: 12

Answer

$2,\ -1,\ -1/2,\ 1/2,\ -1,\ -2,\ 2,\ -1,\ -1/2,\ 1/2$

Work Step by Step

$\left[\begin{array}{ll} n & a_{n}\\ \\ 1.\ & 2\\ \\ 2.\ & -1\\ \\ 3.\ & \frac{-1}{2}= -\frac{1}{2} \\ \\ 4.\ & \frac{-1/2}{-1}= \frac{1}{2} \\ \\ 5.\ & \frac{1/2}{-1/2}= -1 \\ \\ 6.\ & \frac{-1}{1/2}= -2 \\ \\ 7.\ & \frac{-2}{-1}= 2 \\ \\ 8.\ & \frac{2}{-2}= -1 \\ \\ 9.\ & \frac{-1}{2}= -\frac{1}{2} \\ \\ 10.\ & \frac{-1/2}{-1}= \frac{1}{2} \end{array}\right]$
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