Answer
$a_n=n^2-1$
Work Step by Step
We can see that the terms represent square numbers, with one subtracted, and $a_1=0=1^2-1$, so $a_n=n^2-1$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 9 - Section 9.1 - Sequences - Exercises - Page 487: 19
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