University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.1 - Sequences - Exercises - Page 487: 15

Answer

$a_n=(-1)^{n+1}n^2$

Work Step by Step

We can see that the subsequent terms are subsequent square numbers, with alternating signs with $a_1=1$, so $a_n=(-1)^{n+1}n^2$ for all $n$ natural numbers.
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