Answer
$a_n=\frac{2^{n-1}}{3(n+2)}$
Work Step by Step
We can see that the subsequent terms' numerator gets multiplied by $2$ and $3$ is added to the denominator with $a_1=\frac{1}{9}$, so $a_n=\frac{2^{n-1}}{3(n+2)}$ for all $n$ natural numbers.
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 9 - Section 9.1 - Sequences - Exercises - Page 487: 17
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
