University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 8 - Section 8.7 - Improper Integrals - Exercises - Page 471: 4



Work Step by Step

Consider $f(x)=\int_{0}^{4} \dfrac{1}{\sqrt {4-x}} dx$ $\lim\limits_{a \to 4^{-}} f(x)= \lim\limits_{a \to 4^{-}} \int_{0}^{a} \dfrac{1}{\sqrt {4-x}} dx=\lim\limits_{a \to 4^{-}} [-2 \sqrt {4-x}]_{0}^{a}$ or, $\lim\limits_{a \to 4^{-}} [-2 \sqrt {4-a}+4]= 4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.