University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 8 - Section 8.7 - Improper Integrals - Exercises - Page 471: 36

Answer

Diverges

Work Step by Step

We have: $\int_{0}^{\pi / 2} \cot \theta d \theta=\lim\limits_{b \to 0^{+}}\int_{0}^{\pi / 2} \cot \theta d \theta\\ =\lim\limits_{b \to 0^{+}} [\ln |\sin \theta|]_{b}^{\pi / 2}\\ =\lim\limits_{b \to 0^{+}}[\ln 1-\ln |\sin b|]\\ =-\lim\limits_{b \to 0^{+}}[\ln |\sin b|]\\ =+\infty$ Thus, the limit does not exist, and so, the integral diverges.
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