University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 8 - Section 8.5 - Integral Tables and Computer Algebra Systems - Exercises - Page 451: 49

Answer

$$\int\csc^5xdx=-\frac{\csc^3x\cot x}{4}-\frac{3\csc x\cot x}{8}-\frac{3}{8}\ln|\csc x+\cot x|+C$$

Work Step by Step

$$A=\int\csc^5xdx$$ Use Reduction Formula 100, which states that $$\int\csc^naxdx=-\frac{\csc^{n-2}ax\cot ax}{a(n-1)}+\frac{n-2}{n-1}\int\csc^{n-2}axdx$$ for $n=5$ and $a=1$ $$A=-\frac{\csc^3x\cot x}{4}+\frac{3}{4}\int\csc^3xdx$$ Apply Formula 100 one more time, for $n=3$ and $a=1$: $$A=-\frac{\csc^3x\cot x}{4}+\frac{3}{4}\Big(-\frac{\csc x\cot x}{2}+\frac{1}{2}\int\csc xdx\Big)$$ $$A=-\frac{\csc^3x\cot x}{4}+\frac{3}{4}\Big(-\frac{\csc x\cot x}{2}-\frac{1}{2}\ln|\csc x+\cot x|\Big)+C$$ $$A=-\frac{\csc^3x\cot x}{4}-\frac{3\csc x\cot x}{8}-\frac{3}{8}\ln|\csc x+\cot x|+C$$
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