University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 8 - Section 8.5 - Integral Tables and Computer Algebra Systems - Exercises - Page 451: 47

Answer

$$\int2\sec^3\pi xdx=\frac{\sec\pi x\tan\pi x}{\pi}+\frac{1}{\pi}\ln|\sec \pi x+\tan\pi x|+C$$

Work Step by Step

$$A=\int2\sec^3\pi xdx$$ Use Reduction Formula 99, which states that $$\int\sec^naxdx=\frac{\sec^{n-2}ax\tan ax}{a(n-1)}+\frac{n-2}{n-1}\int\sec^{n-2}axdx$$ for $n=3$ and $a=\pi$ $$A=2\Big[\frac{\sec\pi x\tan \pi x}{2\pi}+\frac{1}{2}\int\sec\pi xdx\Big]$$ $$A=\frac{\sec\pi x\tan\pi x}{\pi}+\int\sec\pi xdx$$ Next, apply Formula 95, which states that $$\int\sec axdx=\frac{1}{a}\ln|\sec ax+\tan ax|+C$$ for $a=\pi$ $$A=\frac{\sec\pi x\tan\pi x}{\pi}+\frac{1}{\pi}\ln|\sec \pi x+\tan\pi x|+C$$
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