University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 9


$\lt 1,-4 \gt$

Work Step by Step

Let us consider $A$ and $B$ as vectors. and, a vector $a$ can be found as: $a=B-A=\lt 2,-1 \gt -\lt 1,3 \gt =\lt 1,-4 \gt$ Hence, our final answer is: $\lt 1,-4 \gt$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.