## University Calculus: Early Transcendentals (3rd Edition)

$5i+3j-k$
Here, $u=\lt -1,0,2 \gt$ and $v=\lt 1,1,1 \gt$ $-2u+3v=-2\lt -1,0,2 \gt +3\lt 1,1,1 \gt =\lt 2,0,-4 \gt +\lt 3,3,3 \gt=\lt 5,3,-1 \gt$ Hence, our final answer is: $-2u+3v=5i+3j-k$