University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 22



Work Step by Step

Here, $u=\lt -1,0,2 \gt$ and $v=\lt 1,1,1 \gt $ $-2u+3v=-2\lt -1,0,2 \gt +3\lt 1,1,1 \gt =\lt 2,0,-4 \gt +\lt 3,3,3 \gt=\lt 5,3,-1 \gt$ Hence, our final answer is: $-2u+3v=5i+3j-k$
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