University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 27



Work Step by Step

Here, $v=0i+0j+5k$ and $|v|=\sqrt{0^2+(0)^2+(5)^2}=\sqrt {25}=5$ The unit vector $\hat{\textbf{v}}$ can be calculated as: $\hat{\textbf{v}}=\dfrac{v}{|v|}$ Now, $\hat{\textbf{v}}=\dfrac{0i+0j+5k}{5}=(0,0,1)$ Thus, $v=|v|\hat{\textbf{v}}=5(1k)=5k$
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