University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 16


$\lt \dfrac{-1}{ \sqrt 2},\dfrac{1}{\sqrt 2} \gt$

Work Step by Step

The coordinates of a point P on the circle with radius $r$ are: $(r \cos \theta, r \sin \theta)$ Therefore, $\lt 1*\cos (135^{\circ}), 1*\sin (135^{\circ}) \gt=\lt \dfrac{-1}{ \sqrt 2},\dfrac{1}{\sqrt 2} \gt$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.