University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 17


$-3 i+2j -k$

Work Step by Step

Let us consider $P_1$ and $P_2$ as vectors and, a vector $\overrightarrow{P_1P_2}$ can be found as: $\overrightarrow{P_1P_2}=\overrightarrow{P_2}-\overrightarrow{P_1}=\lt 2,9,-2 \gt -\lt 5,7,-1 \gt =\lt -3,2,-1 \gt$ Hence, our final answers is: $\overrightarrow{P_1P_2}=-3 i+2j -k$
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